This doesn't look all that different from the previous example, and even though our activitiy is split between two different symbols, the results are the same. Since the logic processor doesn't return any results until after all the evaluations are done, we (and any other symbols that may have 'target_signal' as an input) only ever see 'target_signal' as being low.Д«ut I started out saying that you can have a buffer with a single 1-enabled input not propogate a high signal on the enable line to the output, right? How's that happen? Well, what I forgot to tell you is that there's another symbol in this program: In the process of evaluating this lone buffer symbol, the logic processor sees two results for 'target_signal' - the first one where it comes out high from the 1 on input 1 - and the second, where it becomes low from the 0 on input 2. (Many will recognize this concept as a 'logic wave') Here's why - when the 2-series logic processor sees 'button_press' go high, it evaluates all the logic immediately connected to it and doesn't return the results until after it is done. If you haven't tried this in a 2-series processor, you might not realize that when 'button_press' goes high, 'target_signal' never does. Guess what? Not so much! Let's digress for a second before we show you what condition just might make 'target_signal' never even hiccup in this program. So you'd think you would see the signal coming out of this symbol going high when the buffer is enabled, 100% of the time, right?

Crestron simpl tutorial